Question

The sum of three consecutive multiples of 11 is 363. Find these multiples. ​

Answer 1

Answer:

Let the three consecutive multiples of 11 are 11x, 11x+11 and 11x+22

Their sum is 363

11x+11x+11+11x+22=363

33x+33=363

33x=363−33

33x=330

x=10

First multiple =11x=11×10=110

Second multiple =11x+11=110+11=121

Third multiple =11x+22=110+22=132

pls mark me as brainlist!!!!!

Answer 2

Given:-

• Sum of three consecutive multiples of 11 is 363.

⠀

To find:-

• Find these multiples.

⠀

Solution:-

★ If x is a multiple of 11, the next multiple is x + 11. The next to this is x + 11 + 11 or x + 22. So we can take three consecutive multiples of 11 as x, x + 11 and x + 22.

※ It is given that the sum of these consecutive multiples of 11 is 363. This will give the following equation:

$\large{\tt{\longmapsto{x + (x + 11) + (x + 22) = 363}}}$

$\large{\tt{\longmapsto{x + x + 11 + x + 22 = 363}}}$

$\large{\tt{\longmapsto{3x + 33 = 363}}}$

$\large{\tt{\longmapsto{3x = 363 - 33}}}$

$\large{\tt{\longmapsto{3x = 330}}}$

$\large{\tt{\longmapsto{x =\dfrac{330}{3}}}}$

$\boxed{\large{\tt{\longmapsto{\red{x = 110}}}}}$

★ Hence, the three consecutive multiples are 110, 121, 132 (answer).

※ We can see that we can adopt different ways to find the solution for the problem.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬