Question

The sum of three consecutive multiples of 11 is 363. Find these multiples. *

Answer 1

Answer:

The answer is

(x+(x+11)+(x+12) = 363

33+3x=363

x=110

hope this helps u

Answer 2

Let the three consecutive multiples of 11

be 11x, 11(x + 1) and 11(x + 2) 11x + 11x + 11 + 11x + 22 = 363

33x = 363 - 33

33x = 330

so,

x= 10

hence,

the multiples are:

11x = 110

11(x+1)= 121

11( x + 2) = 132