Question

the sum of three consecutive multiples of 11 is 363 .find these multiples

Answer 1

Hey there !!

Let three consecutive multiples of 11 are x, (x+11) and (x+22).

x + (x+11) + (x+22) = 363

3x + 33 = 363

3 ( x + 11 ) = 363

( x + 11 ) = 363 / 3

x + 11 = 121

x = 121 – 11

x = 110

Thus, the multiples are x i.e, 110, (x + 11) i.e, 110 + 11 = 121 and (x + 22) i.e., 110 + 22 = 132.

Answer 2

Hey Mate!
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Here is your answer :
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Given,

Sum of the three multiples of 11 = 363

Let the multiples be x , x + 11 , x + 22

ATP,

x + x + 11 + x + 22 = 363

3x + 33 = 363

3x = 363 - 33

3x = 330

x = 330/3

x = 110

Therefore,

the multiples are :

x = 110

x + 11 = 110 + 11 = 121

x + 22 = 110 + 22 = 132


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