Question

the sum of three consecutive multiples of 11 is 363 find these multiples​

Answer 1

Answer:

one be n+1, n+2, n+3

then,

3n +6= 363

3n = 357

n = 357/3

n = 119

no. are - 120,121,122

Answer 2

Answer:

110 , 121 , 132

Step-by-step explanation:

Let the three consecutive multiples of 11 are 11x, 11x+11 and 11x+22

Their sum is 363

11x+11x+11+11x+22=363

33x+33=363

33x=363−33

33x=330

x= 33/330

x=10

First multiple =11x=11×10=110

Second multiple =11x+11=110+11=121

Third multiple =11x+22=110+22=132