the sum of three consecutive multiples of 11 is 363 .find these multiples
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Answered by
85
hey there
here is your answer
let one number be x . let the second number be x + 11 . let the third number be x + 22
x + x + 11 + x + 22 = 363
3x + 33 = 363
3x = 363 - 33 = 330
3x = 330
x = 110
x + 11 = 121
x + 22 = 132
hope it helps you :-)
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here is your answer
let one number be x . let the second number be x + 11 . let the third number be x + 22
x + x + 11 + x + 22 = 363
3x + 33 = 363
3x = 363 - 33 = 330
3x = 330
x = 110
x + 11 = 121
x + 22 = 132
hope it helps you :-)
please mark as brainliest
soniritik:
hmmmmmm
Answered by
15
Let the first multiple be x.Let the second multiple be x+11.Let the third multiple be x+22.According to the questionx+x+11+x+22=3633x+33 =363x=110So the first multiple is 110,
second multiple is 121 and
the third multiple is 132.
second multiple is 121 and
the third multiple is 132.
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