Question

the sum of three consecutive multiples of 11 is 363.find these multiple.
answer it correctly and fastly please​

Answer 1

QUESTION:-

the sum of three consecutive multiples of 11 is 363.find these multiple.

EXPLANATION:-

Since the numbers are consecutive .So let the numbers be:-

x,x+1,x+2

Multiplying them by 11 we get:-

11x ,11x+11 ,11x+22

Their sum is 363     (given)

11x+133x+33=363

33x=363−33

33x=3301x+11+11x+22

x=330/33

x=10

So .

First multiple  =11x=11×10=110

Second multiple  =11x+11=110+11=121

Third multiple  =11x+22=110+22=132

Answer 2

Answer :-

The multiples of 11 are 110, 121 and 132.

Step-by-step Explanation

To Find :-

• The multiples.

★ Solution :-

Given that,

• The sum of three consecutive multiples of 11 is 363.

Assumption

Let us assume the three multiples as (x), (x + 1) and (x + 2).

According the question,

→ 11(x) = 11x

→ 11(x + 1) = 11x + 11

→ 11(x + 2) = 11x + 22

Therefore,

• 11x + (11x + 11) + (11x + 22) = 363

On solving,

→ 11x + (11x + 11) + (11x + 22) = 363

→ 11x + 11x + 11 + 11x + 22 = 363

→ 11x + 11x + 11x + 11 + 22 = 363

→ 33x + 33 = 363

→ 33x = 363 - 33

→ 33x = 330

→ x = 10

After solving, We got.

The value of x as 10.

______________________

Now, The multiples are :-

• 11x = 11*10 = 110
• (11x + 11) = 11*10 + 11 = 121
• (11x + 22) = 11*10 + 22 = 132.

Hence, The multiples are 110, 121 and 132.