The sum of three consecutive multiples of 11 is 363 find its multiples
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the three multiples are 110,121,132
then the sum will be 110+121+ 132 = 363
then the sum will be 110+121+ 132 = 363
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Answer: 110 , 121 and 132
Step-by-step explanation:
Let the number's be x , x+11 , x+22.
x + x + 11 + x + 22 = 363
3x + 33 = 363
3x = 363 - 33 = 330
x = 330/3 = 110
x + 11 = 110 + 11 = 121
x + 22 = 110 + 22 = 132
Hence, the number's are 110 ,121 and 132.
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