Question

The sum of three consecutive multiples of 11 is 363. find the least numbers.
please answer asap

Answer 1

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★Let the three multiples of 11 be 11x,

11x+11, 11x+11+11( = 11x+ 22)

✪Their sum is = 363

A/q

11x + 11x + 11 + 11x + 22 = 363

⇒ 33x + 33 = 363

⇒ 33x = 363 - 33 = 330

⇒ x = 330/33 = 10

☞Least number = 11x = 11*10 = 110

Answer 2

Answer: 110 , 121 and 132

Step-by-step explanation:

Let the number's be x , x+11 , x+22.

x + x + 11 + x + 22 = 363

3x + 33 = 363

3x = 363 - 33 = 330

x = 330/3 = 110

x + 11 = 110 + 11 = 121

x + 22 = 110 + 22 = 132

Hence, the number's are 110 ,121 and 132.

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