Question

The sum of three consecutive multiples of 11 is 363 .find the multiples​

Answer 1

Answer:

Let the three consecutive multiples of 11 are 11x, 11x+11 and 11x+22

Their sum is 363

11x+11x+11+11x+22=363

33x+33=363

33x=363−33

33x=330

x=

33

330

x=10

First multiple =11x=11×10=110

Second multiple =11x+11=110+11=121

Third multiple =11x+22=110+22=132

Explanation:

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Answer 2

Answer:

110, 121, 132 are the multiples

Explanation:

Let the three consecutive multiples of 11 be x+11, x+22, and x+33

So,

x+11 + x+22 + x+33 = 363

3x + 66 = 363

3x = 363 - 66

3x = 297

x = 297/3

x = 99

The three consecutive multiples are:

x+11= 99+11 = 110

x+22 = 99+22 = 121

x+33 = 99+33 = 132

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