Question

the sum of three consecutive multiples of 11 is 363. then the least multiple is​

Answer 1

Step-by-step explanation:

let three consecutive multiples of 11 are 11x , 11(x+1) , 11(x+2)

sum = 11x + 11(x+1) + 11(x+2) = 363

11x+11x+11+11x+22=363

33x + 33 = 363

33(x+1) = 363

x+1 = 363/33

x+1 = 11

x = 10

The least multiple among the three is 11x = 11(10) = 110

other two multiples are

11(x+1 ) = 11(10+1) = 11*11 = 121

11(x+2) = 11(1o+2) = 11 *12 = 132

therefore option is C

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Answer 2

Answer:

Step-by-step explanation: