Question

The sum of three consecutive multiples of 11 is 468. Find these multiples.

This is The Exact Question​

Answer 1

Answer:

here the question should be 462 instead of 468

so then

(11*X)+(11*(X+1))+(11*(X+2))=462

11X+11X+11+11X+22=462

33X+33=462

11(3X+3)=462

3X+3=462/11

3X+3=42

3(X+1)=42

X+1=42/3

X+1=14

X=13

hence multiples are

(11*13)+(11*14)+(11*15)=462