Question

the sum of three consecutive multiples of 11 is 594 . find the multiples.​

Answer 1

Answer:

the multiples are 187,198,209

Step-by-step explanation:

let consecutive multiples of 11 be x,x+11,x+22(where x is any multiple of 11)

x+x+11+x+22=594

3x+33=594

3x=594–33

3x=561

x=187

x=187

x+11=187+11=198

x+22=187+22=209

Answer 2

To find : three consecutive multiples of $11$ .

Given : sum of three consecutive multiples of $11$ is $594$.  

Solution :

• As per the given data we are given that  sum of three consecutive multiples of $11$ is $594$.  

• Let three multiples be $x$ , $x + 11$ and $x + 22$ .
• We represent given condition as : $x + ( x + 11 ) + ( x+ 22) = 594$

       $\begin{array}{l}\mathrm{x}+(\mathrm{x}+11)+(\mathrm{x}+22)=564 \\\therefore 3 \mathrm{x}+33=564 \\\therefore 3 \mathrm{x}=594-33 \\\therefore 3 \mathrm{x}=561 \\\mathrm{x}= 187\end{array}$

• multiples are : $x = 187$

                               $x + 11 = 198$

                               $x + 22 =209$

Hence , multiples are $187, 198 , 209$ .