The sum of three consecutive multiples of 11 is 852. Find the multiples
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Answered by
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Step-by-step explanation:
Let the three consecutive multiples of 11 are 11x, 11x+11 and 11x+22
Their sum is 363
11x+11x+11+11x+22=363
33x+33=363
33x=363−33
33x=330
x=
33
330
x=10
First multiple =11x=11×10=110
Second multiple =11x+11=110+11=121
Third multiple =11x+22=110+22=132
Answered by
0
Answer:
110,121,132
Step-by-step explanation:
Let the three consecutive multiples of 11 are 11x, 11x+11 and 11x+22
Their sum is 363
11x+11x+11+11x+22=363
33x+33=363
33x=363−33
33x=330
x=
33
330
x=10
First multiple =11x=11×10=110
Second multiple =11x+11=110+11=121
Third multiple =11x+22=110+22=132
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