Question

The sum of three consecutive multiples of 11 is 99, then multiples are ​

Answer 1

Answer:

The multiple are 22,33 and 44.

Answer 2

Answer:

1st number:-. 22

2nd number:- 33

3rd number:-. 44

Step-by-step explanation:

$1st \: numbr = 11x \\ 2nd \: number = 11x + 11 \\ 3rd \: number = 11x + 22 \\ 11x + 11x + 11 + 11x + 22 = 99 \\ 33x + 33 = 99 \\ 33x = 99 - 33 \\ x = \frac{66}{33} \\ x = 2 \\ 1st \: numer = 11x = 11 \times 2 = 22 \\ 2nd \: nuber = 11x + 11 = 11 \times 2 + 11 = 33 \\ 3rd \: number = 11x + 22 = 11 \times 2 + 22 = 44$