Question

The sum of three consecutive multiples of 11is 363 .find the multiple​

Answer 1

Answer:

let the multiples be x

so x,(x+11),(x+22)

are three consecutive multiple of 11

so, x+(x+11)+(x+22)=363

=x+x+11+x+22=363

=3x+33=363

=3x=363-33

=3x=330

=x=330/3

=x=110

so value of x = 110

so three multiple are

x=110

x+11=110+11=121

x+22=110+22=132

this is the answer

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Answer 2

Answer:

110 , 121 , 132

Step-by-step explanation:

given that,

The sum of three consecutive multiples of 11 is 363

let 1st number be 11x [multiple of 11]

so,

next numbers = 11(x + 1 ) , 11(x + 2)

given sum of the numbers

= 363,

so,

According to the question,

11x + 11(x + 1) + 11(x + 2) = 363

➡11(x + x + 1 + x + 2) = 363

➡3x + 3 = 363/11

➡3x + 3 = 33

➡3x = 33 - 3

➡3x = 30

➡x = 30/3

✔x = 10

now,

numbers

➡11x = 11(10)

➡ 110

_________________

➡11(x + 1)

➡11(10 + 1)

➡11 × 11

= 121

_________________

➡11(x + 2)

➡11(10 + 2)

➡11 × 12

= 132

so,

numbers are

110 , 121 , 132