The Sum of three consecutive multiples of 12 is 216. find these multiples
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Let the consecutive multiples of number be 12 x , 12(x+2),12(x +3)
According to the question , :)
Sum of three consecutive multiples of 12 is 216 .
So , 12x +12(x+1)+12(x+2)= 216
12x + 12x +12 + 12x+24=216
36x +36=216
36x = 216-36 = 180
x = 180 ÷ 36 =6
Now, The Answer is 6 .
YOU WILL GET THE MULTIPLE WHEN U ADD 6 INSTEAD OF X...
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