Question

the sum of three consecutive multiples of 12 is 324 what are the multiples

Answer 1

1st consecutive No. x
2nd consecutive no.(x+1)
3rd consecutive no.(x+2).
Multiple of 12. 【GIVEN】
A/q:
solve-
=(x+x+1+x+2)12=324
=12x+12x+12+12x+24=324
=36x+36=324
=36x=324-36
=36x=288
=x=288/36
=x= 8
Now,
1st No.=x=8
2nd No.=x+1=8+1=9
3rd No.=x+2=8+2=10 Answer.
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Answer 2

Answer:

The three consecutive multiples of 12 such that their sum is 324 is  312, 324, 336

Step-by-step explanation:

Given,

The sum of three consecutive multiples of 12 = 324

Solution:

Required to find the multiples of 12 such that the sum of three consecutive multiples of 12 = 324

Let one multiple of 12 be 12x

The multiple of 12 just before 12x = 12x-12

The multiple of 12 just after 12x = 12x+12

Hence three consecutive multiples of 12 are 12x-12, 12x, 12x+12

Since it is given that the sum of three consecutive multiples of 12 is 324

12x -12 +12x + 12x +12 = 324

36x = 324

x = $\frac{324}{36}$ = 27

Hence the three consecutive multiples of 12 are 12×27 - 12, 12×27, 12×27 +12

= 312, 324, 336

The three consecutive multiples of 12 such that their sum is 324 is  312, 324, 336

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