The sum of three consecutive
multiples of 13 is
548. Find the multiples
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Answer:
13(x)+13(x+1)+13(x+2)
13x+13x+13+13x+26=548
39x+39=548
39x=548-39
39x=509
x=13
then the multiples
[1] 13(13)=169
[2]13(13+1)=182
[3]13(13+2)=195
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