The sum of three consecutive multiples of 13 is 585. Find these multiples.
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Answered by
5
Answer:
let the three consecutive multiples of 13 be x
so the three consecutive multiples are x,x+13,x+26
=x+(x+13)+x+26)=585
=(x+x+x)+(26+13)=585
=3x=585-39
=3x=546
=x=546/3=182
so the three consecutive multiples are
x=182;x+13=195;x+26=208
182,195,208.
Answered by
1
Hey mate, here is your solution
let the three consecutive multiples of 13 be x
so the three consecutive multiples are x,x+13,x+26
=x+(x+13)+x+26)=585
=(x+x+x)+(26+13)=585
=3x=585-39
=3x=546
=x=546/3=182
so the three consecutive multiples are
x=182;x+13=195;x+26=208
182,195,208.
Hope it helps you
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