Question

The sum of three consecutive multiples of 2 is 120. Find the multiples.​

Answer 1

Answer:

let the 3 numbers be 2x-2,2x and 2x+2

now

2x+2 +2x +2x-2 = 120

6x = 120

x = 20

so the three numbers are

38 40 and 42

Explanation:

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Answer 2

Answer:

38, 40, 42

Explanation:

Let the first multiple of 2 be 'x'

Then the second multiple of 2 = x+2

And the third multiple of 2 = x+2+2 = x+4

According to the question,

(x)+(x+2)+(x+4)=120

⇒ x+x+x+2+4 = 120

⇒ 3x+6 = 120

⇒ 3x = 120-6

⇒ 3x = 114

⇒ x = 114/3

⇒ x = 38

Therefore, the three multiples of 2 are

x = 38

x+2 = 38+2 = 40

x+4 = 38+4 = 42