Question

The sum of three consecutive multiples of 2 is 18 find the numbers(Hint:let the multiples be x , x+2 , x+4 )

Answer 1

Let the numbers be x,x+2,x+4

$x + x + 2 + x + 4 = 18$

$3x + 6 = 18$

$3x = 18 - 6$

$3x = 12$

$x = \frac{12}{3}$

$x = 4$

The numbers are

x=4

x+2=4+2=6

x+4=4+4=8

Therefore the numbers are 4,6,8.

Answer 2

Answer:

HII GUYS

THE SOLUTIONS OF THIS QUESTION :-

Step-by-step explanation:

LET the first multiple of 2 be x.

then consecutive multiple be=

=x,x+2,x+4

A/Q

sum of multiple =18

hence,

x+x+2+x+4=18

3x+6=18

3x=18-6

3x=12

x=12/3

x=4

so the numbers are

x=4

x+2=6

x+4 =8

hope it helps you all a lot....