Question

The sum of three consecutive multiples of 3 is 108 find the multiples

Answer 1

Step-by-step explanation:

let multiples be 3x, 3(x+1),3(x+2)

therefore,

3(x)+3(x+1)+3(x+2)=108

3(3x+3)=108

3x+3=39

3(x+1)=39

(x+1)=13

x=12

Answer 2

The multiples are 11, 36 and 39.

Given - Type of multiples and their sum

Find - Multiples

Solution - Let the multiples be 3x, 3(x+1) and 3(x+2).

Multiples = 3x, 3x + 3, 3x + 6

Forming the equation -

$3x + 3x + 3 + 3x + 6 = 108$

$9x + 9 = 108$

$9x = 108 - 9$

$9x = 99$

$x = \frac{99}{9}$

$x = 11$

First multiple = 11

Second multiple = 3(x + 1)

Second multiple = 3(11 + 1)

Second multiple = 33 + 3

Second multiple = 36

Third multiple = 3(x + 2)

Third multiple = 3(11 + 2)

Third multiple = 33 + 6

Third multiple = 39

Hence, the multiples are 11, 36 and 39.

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