The sum of three consecutive multiples of 3 is 108. The multiples are:
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Answered by
1
Answer:
Ok
Step-by-step explanation:
Let the multiples be =x,x+3,x+6
According to the question =>>
X+x+3+x+6=108
3x+9=108
3x=108-9
3x=99
X=33
So the numbers are =33,36,39
Answered by
2
Answer:
mark the above ans as brainliest.....
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