The sum of three consecutive multiples of 3 is 315. Find them
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Answered by
22
This statement can be expressed as...
3(n) + 3(n+1) + 3(n+2) = 315
3n + 3n + 3 + 3n + 6 = 315
9n + 9 = 315
9n = 306
n=34
Hence, multiples of 3 are 34, 35 and 36.
Answered by
27
3x+ 3(x+1)+3(x+2)=315
3x + 3x +3+ 3x + 6 = 315
9x. = 315 - 9
9x = 306
x =306 / 9
x = 34
therefore,
first number= 3x = 3*34= 102
second number = 3(x+1)= 3(34+1)=3*35= 105
third number= 3(x+2)=3(34+2)=3*36=108
3x + 3x +3+ 3x + 6 = 315
9x. = 315 - 9
9x = 306
x =306 / 9
x = 34
therefore,
first number= 3x = 3*34= 102
second number = 3(x+1)= 3(34+1)=3*35= 105
third number= 3(x+2)=3(34+2)=3*36=108
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