Question

The sum of three consecutive multiples of 3 is 333. Find the numbers.

Answer 1

Step-by-step explanation:

three conecutive multiples are 108 , 111 and 114

Answer 2

Step-by-step explanation:

$\mathcal\red{Multiples~of3~:-}\green{3~6~... }$

$\mathcal\red{Let \: the \: number}$= x

so the three consecutive multiples = x-3 , x , x+3

$</strong><strong>\</strong><strong>r</strong><strong>e</strong><strong>d</strong><strong>{</strong><strong>(x - 3) + (x) + (x + 3)</strong><strong>}</strong><strong> = 333 \\ \\ </strong><strong>\</strong><strong>r</strong><strong>e</strong><strong>d</strong><strong>{</strong><strong>3x</strong><strong>}</strong><strong> = 333 \\ \\ </strong><strong>\</strong><strong>r</strong><strong>e</strong><strong>d</strong><strong>{</strong><strong>x</strong><strong>}</strong><strong> = \frac{333}{3} \\ \\ |</strong><strong>\</strong><strong>r</strong><strong>e</strong><strong>d</strong><strong>{</strong><strong>x</strong><strong>}</strong><strong> = 111|$

so, the numbers are :-

$\blue{(x - 3)} \\ = > \blue{111 - 3} \\ = > \blue{108} \\ \\ \pink{(x) = 111} \\ \\ \green{(x + 3)} \\ = > \green{111 + 3} \\ => \green{114}$

(x-3), x, (x+3) = 108 , 111 , 114

:. The numbers are :- 108 , 111 , 114