Question

The sum of three consecutive multiples of 3 is 333. Find the numbers

Answer 1

• The numbers are 108, 111, 114

Step by Step explanation:

Given:

The sum of three consecutive multiples of 3 is 333.

To find:

The numbers

Let the numbers be x, (x+3), (x+6)

[As they are multiples of 3]

Now,

According to the question,

• Their sum is 333

⇒ x + (x+3) + (x+6) = 333

⇒ x + x + x + 3 + 6 = 333

⇒ 3x + 9 = 333

⇒ 3x = 333 - 9

[by taking 9 to RHS]

⇒ 3x = 324

⇒ x = 324 ÷ 3

[By taking 3 to RHS]

⇒ x = 108

Now,

The numbers are

→ x = 108

→ (x + 3) = 108 + 3 = 111

→ (x + 4) = 108 + 6 = 114

----

Verification:

Their sum is 333

So,

108 + 111 + 114

= 219 + 114

= 333

Answer 2

Solution :-

Let,

The Numbers be x, x + 3, x + 6.

According To The Question,

x + x + 3 + x + 6 = 333.

⇒ 3x + 9 = 333.

⇒ 3x = 333 - 9.

⇒ 3x = 324.

⇒ x = 324/3.

⇒ x = 108.

Now,

• First Number = x = 108.

• Second Number = x + 3 = 114.

• Third Number = x + 6 = 117.