Question

The sum of three consecutive multiples of 3 is 45 find the three number
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Answer 1

Answer:

the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45. ATQ,=> X+X+3+X+6=45=> 3x+9=45=> 3x=45-9=> 3x=36=> x=36/3=> x=12thus, the multiples of 3 is 12,15 and 18and 18 is the greatest multiple among them. Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45.

Answer 2

Question

The sum of three consecutive multiples of 3 is 45 find the three number.

Answer

$\sf \: = let \: \: the \: \: three \: \: multiples \: \: of \: \: 3 \: \: bee \\ \\ \sf \: = \: 3x \: \: and \: 3x + 3 \: \: and \: \: 3x + 6 = 45 \\ \\ \sf \: = 3x + 3x + 3x + (3x + 6) = 45 \\ \\ \sf \: = 6x + 3 + 9x = 45 \\ \\ \sf \: = 9x + 9x = 45 \\ \\ \sf \: = 9x = 45 - 9x \\ \\ \sf \: = 9x = 36 \\ \\ \sf \: = \: x = \frac{ 36}{9} = 4 \\ \\ \sf \: = x = 4 \\ \\ \tt \: now \: \: to \: \: find \: \: the \: \: three \: \\ \tt \: number \\ \\ \sf \: = 1st \: \: number3 \times 4 = 12 \\ \\ \sf \: = \: 2nd \: \: number \: = 12 + 3 = 15 \\ \\ \sf \: = \: 3rd \: number = 15 + 3 = 18$