Question

the sum of three consecutive multiples of 3 is 45 find the greatest multiple among them​

Answer 1

Answer:

12,15,18

Step-by-step explanation:

Let the multiples of 3 be x, x+3 and x+6

x + x + 3 + x + 6 = 45

3x + 9 = 45

3x = 36

x = 12

First multiple = x = 12

Second multiple = x + 3 = 12 + 3 = 15

Third multiple = x + 6 = 12 + 6 = 18

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Answer 2

Answer:

Answer:let the number be X

Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6

Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45.

Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45.ATQ,

Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45.ATQ,=> X+X+3+X+6=45

Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45.ATQ,=> X+X+3+X+6=45=> 3x+9=45

Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45.ATQ,=> X+X+3+X+6=45=> 3x+9=45=> 3x=45-9

Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45.ATQ,=> X+X+3+X+6=45=> 3x+9=45=> 3x=45-9=> 3x=36

Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45.ATQ,=> X+X+3+X+6=45=> 3x+9=45=> 3x=45-9=> 3x=36=> x=36/3

Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45.ATQ,=> X+X+3+X+6=45=> 3x+9=45=> 3x=45-9=> 3x=36=> x=36/3=> x=12

Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45.ATQ,=> X+X+3+X+6=45=> 3x+9=45=> 3x=45-9=> 3x=36=> x=36/3=> x=12thus, the multiples of 3 is 12,15 and 18

Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45.ATQ,=> X+X+3+X+6=45=> 3x+9=45=> 3x=45-9=> 3x=36=> x=36/3=> x=12thus, the multiples of 3 is 12,15 and 18and 18 is the greatest multiple among them.

Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45.ATQ,=> X+X+3+X+6=45=> 3x+9=45=> 3x=45-9=> 3x=36=> x=36/3=> x=12thus, the multiples of 3 is 12,15 and 18and 18 is the greatest multiple among them.