Question

The sum of three consecutive multiples of 3 is 63.find the smallest multiple

Answer 1

Answer:

Let the first consecutive multiple of three be x.

Then, second consecutive multiple of three=x+3

& third consecutive multiple of three

= x + 6

according to the question,

x + x + 3 + x + 6 = 63

or, 3x = 63 - 9

or, 3x = 54

or, x = 54/3

x = 18

Therefore, 1st multiple = x =18

2nd multiple = x+3 = 18+3 = 21

3rd multiple = x+6 = 18+6 = 24

Hence the smallest multiple is 8.

Answer 2

Answer:

34 Hai bhai please chahe aap karke