The sum of three consecutive multiples of 3 is 72. Find the number.
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Three numbers would be x, x+1,x+2
x+x+1+x+2=72
3x+3=72
3x=72-3
3x=69
x=69/3=23
First no. =23
Second no. =13+1=24
Third no. =24+2=26
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