Question

The sum of three consecutive multiples of 3 is 72. Find the numbers
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Answer 1

Answer:

let the three consecutive multiples be x, x+3, x+6

by question

x+x+3+x+6 = 72

= 3x+9 = 72

= 3x = 72-9

= 3x = 63

= x = 63/3 = 21

therefore the three consecutive multiples are

x = 21, x+3 = 21+3 = 24, x+6 = 21+6 = 27