Question

the sum of three consecutive multiples of 3 is 72. what is the largest number

Answer 1

Lets assume that the first multiple of 3 is x.
Then the second consecutive multiple of 3 will be (x + 3 )and the second consecutive multiples of 3 will be (x + 6) so by adding these three numbers

(x)+(x+3)+(x+6) = 72
x= 21

So, the largest among these three numbers will be X + 6 = 21 + 6 = 27

Solved :-)

Answer 2

Hi ,

Let 3x , ( 3x + 3 ) and ( 3x + 6 ) are

three consecutive multiples of 3 .

According to the problem given ,

Sum of the three numbers = 72

3x + 3x + 3 + 3x + 6 = 72

9x + 9 = 72

9x = 72 - 9

9x = 63

x = 63/9

x = 7,

Therefore ,

Required three consecutive numbers

are ,

3x = 3 × 7 = 21

3x + 3 = 3 × 7 + 3 = 24 ,

3x + 6 = 3 × 7 + 6 = 27

Largest number = 27

I hope this helps you.

: )