The sum of three consecutive multiples of 3 is 867 find the numbers
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Answer:
286 , 289 , 292
Step-by-step explanation:
let 3x,3( x + 1),3(x + 2) are three consequtive multiples of 3
their sum is 867
3x + 3(x + 1) + 3(x + 2) = 867
3x + 3x + 3 + 3x + 6 = 867
9x + 9 = 867
9x = 867 - 9
9x = 858
x = 95.3
3x = 3(95.3) = 286
3x + 3 = 286 + 3 = 289
3x + 6 = 286 + 6 = 292
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