Question

the sum of three consecutive multiples of 3 is72 . find the value ​

Answer 1

Answer:

Let the three consecutive multiples of 3 be 3x, 3(x + 1) and 3 ( x + 2), i.e. 3x + 3 and 3x + 6

Given, 3x +3x + 3 + 3x +6 = 72

⇒ 9x + 9 = 72 ⇒ 9x=63 ⇒ x =7

∴ Largest multiple of 3 = 3 (x + 2) =3 (7 + 2)

3 x 9 = 27

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let the 1 number be x

let the 2 number be x+3

let the 3 number be x+6

x+(x+3)+(x+6)=72

3x+9=72

3x=72-9

x=63/3

x=21