Question

The sum of three consecutive multiples of 4 is 144. Find these multiples​

Answer 1

Answer:

A/Q

4(x)+4(x+1)+4(x+2)

4x+4x+4+4x+8

12x+12=144

12x=144-12

12x=132

x=132/12

×=11

first multiple=x=11

second multiple=(x+1)=11+1=12

third multiple=(x+2)=11+2=13

Answer 2

44 < 48 < 52

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