the sum of three consecutive multiples of 4 is 324 . find the multipes
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Three consecutive mutiples of four are
➡ (x + 4) ; (x + 8) ; (x + 12) [Assuming]
✦ According to the question,
⇒ (x + 4) + (x + 8) + (x + 12) = 324
⇒ 3x + 24 = 324
⇒ 3x = 324-24
⇒ 3x = 300
⇒ x = 100
Therefore,
The numbers are :
➡ (x + 4) = 104
➡ (x + 8) = 108
➡ (x + 12) = 112
✦ Verification :
As it is told that there sum is equal to 324
Again,
⇒ (x + 4) + (x + 8) + (x + 12) = 324
✦ From the given values :
⇒ 104 + 108 + 112 = 324
⇒ 324 = 324
✦ Hence,
L. H. S. = R. H. S.
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