Question

the sum of three consecutive multiples of 4 is 324 . find the multipes​

Answer 1

Step-by-step explanation:

$\huge{\underline{\bf{{AnsWer :}}}}$

Three consecutive mutiples of four are

➡ (x + 4) ; (x + 8) ; (x + 12) [Assuming]

✦ According to the question,

⇒ (x + 4) + (x + 8) + (x + 12) = 324

⇒ 3x + 24 = 324

⇒ 3x = 324-24

⇒ 3x = 300

⇒ x = 100

Therefore,

The numbers are :

➡ (x + 4) = 104

➡ (x + 8) = 108

➡ (x + 12) = 112

✦ Verification :

As it is told that there sum is equal to 324

Again,

⇒ (x + 4) + (x + 8) + (x + 12) = 324

✦ From the given values :

⇒ 104 + 108 + 112 = 324

⇒ 324 = 324

✦ Hence,

L. H. S. = R. H. S.

${\bf{\huge {\green{\underline{Hence, verified }}}}}$

Answer 2

Answer:

104,108,112

Step-by-step explanation:

let the 1st multiple be n,

so,

n+n+4+n+8=324

3n+12=324

3n=324-12

3n=312

n=312/3

n=104

so,

n=104

n+4=108

n+8=112

Verify:

104+108+112=324