The sum of three consecutive multiples of 4 is 36.Then the required multiples are,
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36,45,54
If p is a multiple of 9, the next multiple is p+9.
According to the question:
⟹p+(p+9)+(p+18)=135
⟹3p+27=135
⟹3p=135−27
⟹3p=108
⟹p=36
Multiples are p,p+9,p+18
36,45,54
Step-by-step explanation:
i just showed a example . sorry . hope u understand
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