Question

The sum of three consecutive multiples of 4 is 444.Find these multiples.

Answer 1

let the no be x,4x, 8x.
x+4x+8x=444
13x=444
x=444/13
x=?
you should take out answer
no1=x
no2=4*x
no3=8*

Answer 2

Answer:

• Let the first multiple of 4 be x and second multiple be (x + 4) and third multiple be (x + 8) ...[Since, the number are consecutive multiple of 4]

$\begin{lgathered}\underline{\boldsymbol{According\: to \:the\: Question\:now :}}$

$:\implies \sf x \: + \: x \: + \: 4 \: + \: x \: + \: 8 \: = \: 444$

$:\implies \sf 3x \: + \: 12 \: = \: 444$

$:\implies \sf 3x \: = \: 444 \: - \: 12$

$:\implies \sf 3x \: = \: 432$

$:\implies \sf x \: = \: \dfrac{432}{3}$

$:\implies\underline{ \boxed{\sf x \: = \: 144}}$

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$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bullet \: \: \underline{\frak {Therefore}}$

$\bullet\:\:\textsf{First multiple of 4 = x = \textbf{144}}$

$\bullet\:\:\textsf{Second multiple of 4 = x + 4 = </p><p>144 + 4 = \textbf{148}}$

$\bullet\:\:\textsf{Third multiple of 4 = x + 8 = 144 + 8 = \textbf{152}}$