Question

The sum of three consecutive multiples of 4 is 60. Find them.​

Answer 1

Answer:

LET THE FIRST NUMBER BE “x”

THEN THE OTHER NUMBERS ARE (x+4) AND (x+8)

THEN,

→x+(x+4)+(x+8)=60

→x+x+4+x+8=60

→3x+12=60

→3x=60-12

→3x=48

→x=48/3

→x=16.

SO,

SUM OF THREE CONSECUTIVE TERMS ARE

x,x+4,x+8

16,16+4,16+8

16,20,24.

Step-by-step explanation:

Answer 2

Answer:

Numbers are 16,20 and 24

Step-by-step explanation:  

The sum of 3 consecutive multiples of 4 is 60.

To find those numbers, let first number is x

then next number which is divisible by 4 is x+4 and next x+8

So, three consecutive multiples of 4 are

x,x+4 and x+8

According to the question

x + x + 4 + x + 8 = 60

3x + 12 = 60

3x = 48

x = 48/3

x = 16

First number is 16,

second is 16+4= 20

and third is x+8=24

Hope it helps you.