The sum of three consecutive multiples of 4 is 60. Find them.
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LET THE FIRST NUMBER BE “x”
THEN THE OTHER NUMBERS ARE (x+4) AND (x+8)
THEN,
→x+(x+4)+(x+8)=60
→x+x+4+x+8=60
→3x+12=60
→3x=60-12
→3x=48
→x=48/3
→x=16.
SO,
SUM OF THREE CONSECUTIVE TERMS ARE
x,x+4,x+8
16,16+4,16+8
16,20,24.
THEN THE OTHER NUMBERS ARE (x+4) AND (x+8)
THEN,
→x+(x+4)+(x+8)=60
→x+x+4+x+8=60
→3x+12=60
→3x=60-12
→3x=48
→x=48/3
→x=16.
SO,
SUM OF THREE CONSECUTIVE TERMS ARE
x,x+4,x+8
16,16+4,16+8
16,20,24.
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