Question

The sum of three consecutive multiples of 5 is 105. What is the second largest number?

Answer 1

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Answer 2

The second-largest number is 35.

Given,

The sum of three consecutive multiples of 5 is 105

To Find,

The second-largest number is =?

Solution,

We can solve the question as follows:

It is given that the sum of three consecutive multiples of 5 is 105. We have to find the second-largest number.

First, let the three consecutive numbers be x, (x + 1), and (x + 2).

Since they are multiples of five, the number will be multiplied by 5. Therefore, the numbers are 5x, 5(x + 1), and 5(x + 2).

Now, their sum is equal to 105. Therefore,

$5x + 5(x + 1) + 5(x +2) = 105$

Solving the above equation to find the value of x,

$5x + 5x + 5 + 5x + 10 = 105$

$15x + 15 = 105$

$15x = 105 - 15$

$15x = 90$

$x = \frac{90}{15} = 6$

Now, the second-largest number is 5(x + 1). Substituting the value of x,

$5( 6 + 1) = 30 +5 = 35$

Hence, the second-largest number is 35.