The sum of three consecutive multiples of 5 is 1110.find these multiples
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Answered by
29
let the three consecutive numbers be x, x+5,x+10.
therefore, according to question,
x +x+5+x+10 =1110
=> 3x+15 =1110
=> 3x = 1110-15
=> x = 365
therefore,
first no. = x= 365
second no.=x+5=365+5=370
third no.=365+10 =375.
☺☺☺
therefore, according to question,
x +x+5+x+10 =1110
=> 3x+15 =1110
=> 3x = 1110-15
=> x = 365
therefore,
first no. = x= 365
second no.=x+5=365+5=370
third no.=365+10 =375.
☺☺☺
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2
Step-by-step explanation:
Same up ans thanks to him I also got the correct answer
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