The sum of three consecutive multiples of 5 is 3015. Find the first multiple numbe
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Let the three consecutive multiples of 5 be 5x, 5(x+1) and 5(x+2).
According to the question,
5x+5(x+1)+5(x+2) = 3015
5(x+x+1+x+2)=3015
5(3x+3)=3015
3x+3=3015/5=603
3x=603-3=600
x=600/3=200
Hope it helps uh.
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