the sum of three consecutive multiples of 5 is 330 find the multiples
Answers
Answer :-
The three consecutive multiples which sums to 330 are 105, 110, 115.
Solution :-
Consider the three consecutive multiples be x, (x + 5), (x + 10)
Sum of three consecutive multiples = 330
⇒ x + (x + 5) + (x + 10) = 330
Remove brackets
⇒ x + x + 5 + x + 10 = 330
⇒ 3x + 15 = 330
Transpose 15 to RHS
⇒ 3x = 330 - 15
⇒ 3x = 315
Transpose 3 to RHS
⇒ x = 315/3
⇒ x = 105
One multiple = x = 105
Second multiple = (x + 5) = (105 + 5) = 110
Third multiple = (x + 10) = (105 + 10) = 115
Therefore the three consecutive multiples which sums to 330 are 105, 110, 115.
GIVEN :
Sum of three consecutive multiple of 5 = 330
Let the multiples be x, x + 5 and x + 10
According to the problem,
x + (x + 5) + (x + 10) = 330
x + x + 5 + x + 10 = 330
3x + 15 = 330
3x = 330 - 15
3x = 315
x = 315/3
x = 105
Other multiples :
x + 5 = 105 + 5 = 110
x + 10 = 105 + 10 = 115
Therefore, the three consecutive multiples are 105, 110 and 115.