Question

the sum of three consecutive multiples of 5 is 330 find the multipal

Answer 1

5(n) + 5(n+1) +5(n+2)=330
Therefore
After solving it
n=21
3 multiples are
5*21,5*22 and 5*23
105,110 and 115

Answer 2

let three consecutive numbers be n,n+1,n+2

5(n)+5(n+1)+5(n+2)=330

5n+5n+5+5n+10=330

15n+15=330

15n=315

n=315/15

n=21

then

n=5

n+1=5+1=6

n+2=5+2=7

then the 3 consecutive numbers are 5,6,7