Question

the sum of three consecutive multiples of 5 is 630. find the multiple

Answer 1

Let the three consecutive multiples of 5 are:

5x, 5x + 5 and 5x + 10

5x + 5x + 5 + 5x + 10 = 630

15x + 15 = 630

Take 15 Common from above equation

x + 1 = 42

x = 41

Hence three nos. Are

5x = 5*41 = 205
5x+5 = 205+5=210
5x+10 = 205+10 = 215


Thanks

Answer 2

The multiples are 205, 210 and 215

GIVEN:- The sum of three consecutive multiples of 5 is 630.

TO FIND:- Multiple

SOLUTION:-

Let the first number be 5x (because it is a multiple of 5)

The second number = 5x + 5

The third number = 5x + 10

According to the sum,

First number + second number + third number = 630

$5x + (5x + 5) + (5x + 10) = 630 \\ 5x + 5x + 5 + 5x + 10 = 630 \\ 15x + 15 = 630 \\ 15x = 630 - 15 \\ 15x = 615$

Dividing both sides by 15

$\frac{15x}{15} = \frac{615}{15} \\ x = 41$

By substituting the values

First number = $5x = 5 \times 41 = 205$

Second number = $5x + 5 = 5 \times 41 + 5 = 210$

Third number = $5x + 10 = 5 \times 41 + 10 = 215$

Hence, the multiples are 205, 210 and 215

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