the sum of three consecutive multiples of 5 is 945 find the largest multiple
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Answered by
1
let first number is x
then next multiples of 5 are x+5 , x+10
according to given condition ,
x + x+5 + x+10 = 945
3x + 15 = 945
3x = 945 -15
3x = 930
x = 310
so first number is 310
next two are 315 and 320
then next multiples of 5 are x+5 , x+10
according to given condition ,
x + x+5 + x+10 = 945
3x + 15 = 945
3x = 945 -15
3x = 930
x = 310
so first number is 310
next two are 315 and 320
Answered by
0
let the first no.be x,
then let the two consecutive multiples of 5 are
x+5, x+10
A.T.Q,
x+x+5+x+10=945
3x+15=945
3x=930
x=310
so, the first no.we get is 310
the next two no.s are 315 and 320
then let the two consecutive multiples of 5 are
x+5, x+10
A.T.Q,
x+x+5+x+10=945
3x+15=945
3x=930
x=310
so, the first no.we get is 310
the next two no.s are 315 and 320
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