the sum of three consecutive multiples of 6 is 1098. Find the numbers?
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let the three consecutive multiples of 6 be x ,x+6 and x+12
A/q,
x+x+6+x+12=1098
3x+18=1098
3x=1098-18
3x=1080
x=360
Hence required three consecutive multiples of 6 are =360,366and 372
A/q,
x+x+6+x+12=1098
3x+18=1098
3x=1098-18
3x=1080
x=360
Hence required three consecutive multiples of 6 are =360,366and 372
rhea37:
thanks
Answered by
4
refer to the photo.
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