Question

The sum of three consecutive multiples of 6 is 36, the multiples are​

Answer 1

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let one of the number = x

given that these numbers are consecutive multiples of 6

the three numbers will be ,

x , x + 6 , x + 12

given that the sum of these three numbers are 36

x +  x + 6 + x +  12 = 36

3x + 18 = 36

3x = 36 - 18

3x = 18

x = 6

x + 6 = 12

x + 12 = 18

therefore the three numbers are 6 , 12 , 18

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